Distance between Mantecal and San Fernando de Apure
The distance from Mantecal to San Fernando de Apure is 214 kilometers by road. Road takes approximately 2 hours and 41 minutes and goes through Apurito.
Shortest distance by air | 188 km ✈️ |
Car route length | 214 km 🚗 |
Driving time | 2 h 41 min |
Fuel amount | 17.1 L |
Fuel cost | 25.5 GBP |
Point | Distance | Time | Fuel | |
Mantecal | 0 km | 00 min | 0.0 L | |
T-19 104 km, 1 h 17 min
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Apurito | 104 km | 1 h 17 min | 0.1 L | |
T-19 111 km, 1 h 23 min
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San Fernando de Apure | 214 km | 2 h 41 min | 16.7 L |
Frequently Asked Questions
How much does it cost to drive from Mantecal to San Fernando de Apure?
Fuel cost: 25.5 GBP
This fuel cost is calculated as: (Route length 214 km / 100 km) * (Fuel consumption 8 L/100 km) * (Fuel price 1.49 GBP / L)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Mantecal to San Fernando de Apure?
Driving time: 2 h 41 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 212 km with a maximum speed 80 km/h = 2 h 38 min
- 2 km with a maximum speed 50 km/h = 2 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Mantecal to San Fernando de Apure by land?
The distance between Mantecal and San Fernando de Apure is 214 km by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Mantecal and San Fernando de Apure respectively.
How far is Mantecal to San Fernando de Apure by plane?
The shortest distance (air line, as the crow flies) between Mantecal and San Fernando de Apure is 188 km.
This distance is calculated using the Haversine formula as a great-circle distance between two points on the surface of a sphere. The start and finish points are the centers of Mantecal and San Fernando de Apure respectively. Actual distance between airports may be different.
How many hours is Mantecal from San Fernando de Apure by plane?
Boeing 737 airliner needs 14 min to cover the distance of 188 km at a cruising speed of 800 km/h.
Small plane "Cessna 172" needs 51 min to flight this distance at average speed of 220 km/h.
This time is approximate and do not take into account takeoff and landing times, airport location and other real world factors.
How long is a helicopter ride from Mantecal to San Fernando de Apure?
Fast helicopter "Eurocopter AS350" or "Hughes OH-6 Cayuse" need 47 min to cover the distance of 188 km at a cruising speed of 240 km/h.
Popular "Robinson R44" needs 53 min to flight this distance at average speed of 210 km/h.
This time is approximate and do not take into account takeoff and landing times, aerodrome location and other real world factors.
What city is halfway between Mantecal and San Fernando de Apure?
The halfway point between Mantecal and San Fernando de Apure is Apurito. It is located about 4 km from the exact midpoint by road.
The distance from Apurito to Mantecal is 104 km and driving will take about 1 h 17 min. The road between Apurito and San Fernando de Apure has length 111 km and will take approximately 1 h 23 min.
Where is Mantecal in relation to San Fernando de Apure?
Mantecal is located 188 km west of San Fernando de Apure.
Mantecal has geographic coordinates: latitude 7.56652, longitude -69.14705.
San Fernando de Apure has geographic coordinates: latitude 7.87879, longitude -67.47178.
Which highway goes from Mantecal to San Fernando de Apure?
The route from Mantecal to San Fernando de Apure follows T-19.
Other minor sections pass along the road:
- T-02: 7 km